If you prove this you’re a pro:

lim(n*sin((4π^2*n^2+x^2)^0.5)) = x^2/(4π) where n tends to infinity and x is a constant. CAREFUL: This is a sequence! n is a positive integer.

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If you prove this you’re a pro:

lim(n*sin((4π^2*n^2+x^2)^0.5)) = x^2/(4π) where n tends to infinity and x is a constant. CAREFUL: This is a sequence! n is a positive integer.

Powered by WPeMatico

Spread the love